[SOUND] For problem 3A, we're going to change the variable. Instead of not knowing the payment, we have worked with our financial adviser to come up with what we can afford for a monthly payment. We now want to calculate how long it will take us to pay down the loan and what our total savings from the accelerated payment will be. Our rate, the frequency, and the loan value all remain the same. However, let's enter negative 3,000 for our monthly payment this time. Remember the loan payment value will be saved as a negative exactly like the output from question 2A. In C63, number of payment, we will use the NPER() function to calculate the total number of payments. Let's start off by typing =nper and looking at the syntax. You will notice we need the other three variables rate, payment, and present value. Let me quickly select those, which generates 35 payments. From here we can divide the number of payments by the frequency to calculate the amount of 2.9 years. We can see in cell C66, this results in savings of $3,817 when compared to the minimum interest payments we calculated in question 2A. Now please try it on your own in question 3B, which revisits the same business from question 2B. [MUSIC]