which we know is equal to mu sub s N, or excuse me, mu sub S h, has

to be less than b over 2. Or B has to be greater than

2 U sub s h, for slipping to occur first.

So, that's the condition that will ensure

it's slipping will, will, conti, happen first.

And so let's just go through a little bit of a thought process here.

If b is greater than 2 mu sub s times N, the crate will slip first.

And so, that means the wider the crate, the more

apt it is to slip before it will tip over.

Now, if b is equal to 2 mu sub s, that means that delta is equal

to b over 2, and we'll write at the corner with my, our normal force.

And so slipping and tipping will occur simultaneously.

And then if indeed B becomes less than 2

times mu sub s N, the crate's going to tip first.

And so that says as the crate gets skinnier, as b

becomes less, you have more tendency for tipping, rather than slipping.

And that should make physical sense to you.

And so, that's a good analysis of this

problem, which deals with Coulomb friction and static equilibrium.

And we'll do another problem with coulomb friction next time.