So let's move forward 1 would be

ADH which would be 3 for A plus 8.5

plus 6 that will give you 17.5 days.

And then we have BF, start B and

then going to F here, 6 plus 10 equals 16.

We have A, E and F 3 plus 3.5

plus 10, 16.5 days.

And we do have B, G, and then I which

will be 6 plus 7.5, 3.5 17.

And we have another A E G and

then I with a total duration of 17.5 and

the last combination is C I with a total duration of 16.

So, in this case what we see in our project

here that we do have actually two critical path.

Because path ADH and

AEGI has the longest path in

the project with 17.5 days

as we can see 17.5 here and

17.5 here.

So in that case, that mean of the normal

distribution is therefore assumed to be 17.5,

the total duration of the project.

Now as we said, we have two critical path.

In this case, for the PERT calculations,

we need to find the path which we will choose for further PERT calculations.