Learn the fundamentals of digital signal processing theory and discover the myriad ways DSP makes everyday life more productive and fun.

Loading...

來自 École Polytechnique Fédérale de Lausanne 的課程

数字信号处理

265 個評分

Learn the fundamentals of digital signal processing theory and discover the myriad ways DSP makes everyday life more productive and fun.

從本節課中

Module 5: Sampling and Quantization

- Paolo PrandoniLecturer

School of Computer and Communication Science - Martin VetterliProfessor

School of Computer and Communication Sciences

To make our life easier we are going to pick Ts = 1, which means that,

my god, n is equal to pi, so general derivation is given into bulk.

We make a couple of claims now.

The space of pi-bandlimited functions is a Hilbert space.

The set of functions 5n of t, which are simply succinct functions shifted

to location n, form an optimal basis for that Hilbert space.

And if x of t is pi-bandlimited,

then the sequence of samples xn is a sufficient representation.

In other words, if we have the samples xn, we can reconstruct xt perfectly and

that's the essence of the sampling theorem.

So the space of pi bandlimited functions is a vector space.

Actually it's a subspace of L2 of R.

This we shall not prove, but it is intuitive because if you add

two bandlimited function, the result will be a bandlimited function.

So that's the closure of the vector space.

The inner product is a standard inner product in L2 of R and

the completeness issue, which is of course, a trickier one is more delicate.

And it we'll not address it here.

Just remember the definition of the inner product, and

the fact that the convolution can be written as an inner product.

Just taking care that we do the change of variable t minus tau,

in one of the two elements of the convolution.

Let us prove that the sync function and its shifts by integer

is an autonormal basis for the pie bandlimited space.

For this we need to show that the inner product between phi n and

phi m is going to be equal to 1 when n is equal to m and 0 otherwise.

So let's write this inner product between phi n and phi m,

we can see that's the same as between phi 0 and shapes of t- n and t- m.

Then we use the fact that sinc function is symmetric in this argument.

So, (t- n) can be changed into (m- t).

Therefore, we have the integral of sinc(t- n) sinc (m -t) dt.

This we can factor as the convolution of two sinc functions shifted

by (m- n) Now we can use a convolution

theorem knowing that a fourier transform of a sinc function is a rect function.

So sinc convulse with sinc at the location,

m- n is 1 over 2 pi's integral of rect square.

And then e to the j omega m- n d omega.

This is simply the integral over minus pi to pi of this

function that we have seen before.

And this is equal to 1, when m is equal to n, 0 otherwise.

With this we have shown that sinc functions are to each other

when shifted by Integers and the sinc function itself is off no more.

So we have an optimal set of vectors in bl of pi, this set of optimal

vectors can be shown to be an optimal basis for bandlimited functions.